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六级英语阅读理解细节题解题技巧

时间:2021-11-29 17:19:11 外语辅导 我要投稿

六级英语阅读理解细节题解题技巧

  英语六级阅读细节题主要目的是考查考生对文中重要事实和细节部分的辨认和记忆能力,有哪些解题技巧呢?为此百分网小编为大家带来大学英语六级阅读理解的细节的解题小技巧。

六级英语阅读理解细节题解题技巧

  英语六级阅读理解部分细节题的解题技巧

  1.若针对举例子、名人言论、特殊符号后的内容出题,只读例子、名人言论、特殊符号前后句内容,即可选出正确答案。

  2.如果只是针对某一段的内容提出问题的话,只看该段内容即可答题,而不必看完全文才做答。

  3.选项中同义词替换的一般是答案,而与原文相同或极其相似的选项一般不是答案项。

  4.选项中有绝对语气词的一般不是正确答案。

  这些语气词有:always, the most, never, all, only, no, none, exclusively, hardly等,而选项中含有不十分肯定的语气词一般是正确选项。这些语气词:may, often, usually, might, could, more or less, possible, not necessarily等。

  5.议论文中,那些符合一般常识的选项,富有深刻哲理,符合一般规律的选项常常是正确答案。

  英语六级阅读细节题解题的三大步骤

  首先,应仔细阅读题目,弄清楚题目的具体要求,读懂选项内容,找出题目或选项中的关键词。细节题问题一般不掺杂主观内容,而是针对文章的某个具体细节,如时间、地点、人物、原因、结果、条件、现象等进行提问,所给选项有三个为干扰项,这些干扰项有的是片面性的,有的'是部分正确的,还有的属于文中并未涉及的。

  然后,利用关键词返回到原文中,找出与原文相对应的句子。关键词的确定是解题的重点。通过研读历年真题不难发现,关键词往往是题目或选项中的专有名词,如人名、地名、数字(年代、时间)等。因为这些词很有特点,考生在快速浏览文章中会很容易发现,所以便很快能够定位相应的细节,从而完成上述解题步骤。如果题目或者选项当中没有很明显的专有名词,考生可以将里面重复性的名词或者动词视为关键词。

  最后,将确定的句子与四个选项进行对照,通常选项的表述与原文句子有所差别,尽管不是文章原句,却是对其进行的同义转述,所以找出正确答案难度不大。在此环节中,考生应注意的是应该认真核对选项,慎重考虑,一定要根据原文句子进行匹配,千万不能想当然,凭空想象。

  英语六级阅读细节题练习题

  The difference between a liquid and a gas is obvious under the conditions of temperature and pressure commonly found at the surface of the Earth. A liquid can be kept in an open container and fill it to the level of a free surface. A gas forms no free surface but tends to diffuse throughout the 11 available; it must therefore be kept in a closed container or held by a gravitational field, as in the 12 of a planet's atmosphere. The distinction was a 13 feature of early theories describing the phases of matter. In the nineteenth century, for example, one theory maintained that a liquid could be "dissolved" in a vapor without losing its identity, and another theory 14 that the two phases are made up of different kinds of molecules. The theories now prevailing take a quite different approach by emphasizing what liquids and gases have in 15 They are both forms of matter that have no 16 structure, and they both flow readily.

  The fundamental similarity of liquids and gases becomes clearly apparent when the temperature and pressure are 17 somewhat. Suppose a closed container 18 filled with a liquid is heated. The liquid expands, or in other words becomes less dense; some of it evaporates. In contrast, the vapor above the liquid surface becomes denser as the evaporated molecules are 19 to it. The combination of temperature and pressure at which the densities become 20 is called the critical point.

  A. added

  B. case

  C. prominent

  D. held

  E. equal

  F. partially

  G. example

  H. previous

  I. space

  J, lifted

  K. permanent

  L. particularly

  M. extended

  N. raised

  0. common

  11. I 12. B 13. C 14. D 15. O 16. K 17. N 18. F 19. A 20. E


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